MATLAB CONTROL SYSTEM TOOLBOX 9 Spécifications Page 250

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11 Reliable Computations
11-4
Conditioning and Numerical Stability
Two of the key concepts in numerical analysis are the conditioning of problems
and the stability of algorithms.
Conditioning
Consider the linear system given by
A =
0.7800 0.5630
0.9130 0.6590
b =
0.2170
0.2540
Thetruesolutionisx = [1, –1]' and youcan calculate it approximately using
MATLAB.
x = A\b
x =
1.0000
–1.0000
format long, x
x =
0.99999999991008
–0.99999999987542
Of course, in real problems you almost never have the luxury of knowing the
true solution. This problem is very ill-conditioned. To see this, add a small
perturbation to
A
E =
0.0010 0.0010
–0.0020 –0.0010
and solve the perturbed system
xe = (A+E)\b
xe =
–5.0000
7.3085
Ax b=
AE+
()
xb=
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